Don't check if the tire is punctured if it has burst
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7a010a6da2
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67c4d9a694
@ -364,6 +364,9 @@ namespace CoopClient
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if (wheel.IsBursted)
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{
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result.BurstedTires |= (ushort)(1 << (int)wheel.BoneId);
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// Tire is bursted so we don't need to check if the tire punctured
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continue;
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}
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if (wheel.IsPunctured)
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@ -402,6 +405,21 @@ namespace CoopClient
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foreach (VehicleWheel wheel in veh.Wheels)
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{
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if ((model.BurstedTires & (ushort)(1 << (int)wheel.BoneId)) != 0)
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{
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if (!wheel.IsBursted)
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{
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wheel.Burst();
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}
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// Tire is bursted so we don't need to check if the tire punctured
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continue;
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}
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else if (wheel.IsBursted)
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{
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wheel.Fix();
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}
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if ((model.PuncturedTires & (ushort)(1 << (int)wheel.BoneId)) != 0)
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{
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if (!wheel.IsPunctured)
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@ -413,18 +431,6 @@ namespace CoopClient
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{
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wheel.Fix();
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}
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if ((model.BurstedTires & (ushort)(1 << (int)wheel.BoneId)) != 0)
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{
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if (!wheel.IsBursted)
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{
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wheel.Burst();
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}
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}
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else if (wheel.IsBursted)
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{
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wheel.Fix();
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}
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}
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}
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