代码优化，去除剑指offer10.1题斐波那契数列最后一种解法中fib[2]=2的一行代码

2019-04-14 11:44:31 +08:00 · 2019-04-14 11:44:31 +08:00 · aa12d4d41a
commit aa12d4d41a
parent 5d79c99864
1 changed files with 0 additions and 1 deletions
--- a/docs/notes/剑指
+++ b/docs/notes/剑指
@ -107,7 +107,6 @@ public class Solution {

    public Solution() {
        fib[1] = 1;
-        fib[2] = 2;
        for (int i = 2; i < fib.length; i++)
            fib[i] = fib[i - 1] + fib[i - 2];
    }